函数y等于根号3cos2x,x属于

y=√2×sin2x×cos2x化简得y=√2/2*sin4x所以函数的振幅为√2/2周期为π/2当x∈（kπ/2-π/8,kπ/2+π/8)时为增函数当x∈（kπ/2+π/8,kπ/2+3π/8)时

f(x)=(√3)sinxcosx+cos2x+1f(x)=(√3)(2sinxcosx)/2+cos2x+1f(x)=(√3/2)sin2x+cos2x+1f(x)=(√7/2)[(√3/2)(2/

f(x)=2√3sinxcosx-cos2x=√3sin2x-cos2x=2(sin2x*√3/2-cos2x*1/2)=2sin(2x-π/6)x=π/12;函数f(x)的图象可以由函数y(x)=2

f(x)=cos2x+√3sin2x=2sin(2x+π/6)最小正周期为2π/2=π最大值为2单调增区间2x+π/6∈[2kπ-π/2,2kπ+π/2]x∈[kπ-π/3,kπ+π/6]所以单调增区

y=e^x²-cos2xy'=2xe^x²-2*(-sin2x)=2xe^x²+2sin2x很高兴为您解答,【胖教育】团队为您答题.请点击下面的【选为满意回答】按钮,

(1)f(x)=a*b=(√3sin2x,cos2x)(cos2x,-cos2x)=√3sin2x*cos2x-cos2x*cos2x=(√3/2)sin4x-(cos4x+1)/2=(√3/2)si

已知函数f(x)=根号3sin2x+cos2x+21求f(x)的最大值及f(x)取得最大值时自变量x集合f(x)=根号3sin2x+cos2x+2=2[(根号3/2)sin2x+(1/2)cos2x]

1.y=2*(根号3/2sin2x+1/2cos2x)=2*(cos∏/6*sin2x+sin∏/6*cos2x)=2sin(2x+∏/6)画图象可知当-∏/2+2k∏-2/3不知对不对

y=cos2x-(√3)sin2x=-2[(√3/2)sin2x-(1/2)cos2x]=-2sin[2x-(π/6)].即y=-2sin[2x-(π/6)].∴该函数的最大值为2.

f(x)=-1+√3sin2x+2cos2x=-1+√7sin(2x+t)想想,你题目cos2x前面的系数2是不是多余的?

再答：再答：如果帮到了你，请采纳，

y'=-sin2x*(2x)'+cos√x*(√x)'=-2sin2x+cos√x/(2√x)

y=sin(2x-π/3)+根号3cos2x=sin2xcosπ/3-cos2xsinπ/3+2sinπ/3cos2x=sin2xcosπ/3+cos2xsinπ/3=sin(2x+π/3)1.振幅=

f(x)=√3sinxcosx+cos2x+1=(√3/2)sin2x+cos2x+1=[(√7)/2][(√3/√7)sin2x+(2/√7)cos2x]+1=[(√7)/2]sin(2x+α)+1

∵f（x）=sin（π3−2x）+cos2x=32cos2x-12sin2x+cos2x=（32+1）cos2x-12sin2x=2+3sin（2x+θ）∴T=2π2=π故答案为：π．

稍等,z应该是x吧再答：再问：是的再问：谢谢你！

y=1／2cos2x+根号3sinx*cosx=sin30cos2x+cos30sin2x=sin(2x+30)增区间为(0,30)(120,180)

不对,因为f（x）=cos2x-2√3sinxcosx=cos2x-√3sin2x=2[sinπ/6cos2x-cosπ/6sin2x]=2sin(π/6-2x)左移5π/12,f（x）=2sin【π

y=√3sin2x+cos2x=2(√3/2*sin2x+1/2*cos2x)=2(sin2xcosπ/6+cos2xsinπ/6)=2sin(2x+π/6)最大值=2此时2x+π/6=π/2+2kπ

解y=√3cos2x+sin2x+1=2(√3/2cos2x+1/2sin2x)+1=2(sin2xcosπ/3+cos2xsinπ/3)+1=2sin(2x+π/3)+1∵sin(2x+π/3)∈[