先化简再求值2m-4分之3-m除以括号m 2-m-2分之5括号其中m=根号2-3
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![先化简再求值2m-4分之3-m除以括号m 2-m-2分之5括号其中m=根号2-3](/uploads/image/f/2039878-46-8.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC2m-4%E5%88%86%E4%B9%8B3-m%E9%99%A4%E4%BB%A5%E6%8B%AC%E5%8F%B7m+2-m-2%E5%88%86%E4%B9%8B5%E6%8B%AC%E5%8F%B7%E5%85%B6%E4%B8%ADm%3D%E6%A0%B9%E5%8F%B72-3)
:(m+2)(m-3)+3(m+1)(m-1)-(2m+3)(2m-1)=m²-m-6+3m²-3-(4m²+4m-3)=-5m-6=-5×(-1/5)-6=-5
m/(m-n)-n/(m+n)+2mn/(m²-n²)=[m(m+n)-n(m-n)+2mn]/(m²-n²)=(m²+n²)/(m
原式=m(m+3)(m-3)-m(m-2)²=m(m²-9)-m(m²-4m+4)=m(m²-9-m²+4m-4)=m(4m-13)=4m²
2m-4分之m-3除以(m-2分之5减m-2)=(m-3)/2(m-2)÷[5/(m-2)-(m+2)(m-2)/(m-2)]=(m-3)/2(m-2)×(m-2)/(3+m)(3-m)=-1/2(m
原式为:m²(m+4)+2m(m²-1)-3m³=m³+4m²+2m³-2m-3m³=4m²-2m=2m(2m-1)再将
m²-m分之m²-2m+1=(m-1)²/m(m-1)=(m-1)/m=(92-1)/92=91/92
第一题化简成:m(m-2)分之(m-1)(m-2)...(m-2)消掉.最简(m-1)/m再问:麻烦详细点,谢谢!!!~~~再答:是那里没看懂?分母是把m提出来,分子是十字相乘法
再答:原式是这个吗再问:不是再问:不是再答:我再写一下再答: 再答:是这个吗再答: 再问:不是再问:m+3分之m减m的平方减9分之6加m减3分之2再问:其中m等于负2再
=m/(m+3)-6/(m²-9)*(m-3)/2=m/(m+3)-3/(m+3)=(m-3)/(m+3)=-5/1=-5再问:题问错了,应该是。先化简,再求值:x+y分之x的平方-y的平方
6m^2-5m(-m+2n-1)+4m(-3m-5/2n-3/4)=6m²+5m²-10mn+5m-12m²-10mn-3m=﹣m²-20mn+2m=﹣m(m+
2分之3m-(2分之5m-1)+3(4-m)=2分之3m-2分之5m+1+12-3m=-4m+13=-4*3+13=1
m(m-3)-(m+3)(m-3)=(m-3)(m-m-3)=-3(m-3)=-3(-4-3)=21
化简:原式=m^2-3m^2+2m^2+m-5m+4=4-4m然后再代入m的值
原式={[3m(m-2)-m(m+2)]/(m+2)(m-2)}/[2m/(m²-4)]=[(3m²-6m-m²-2m)/(m²-4)]/[2m/(m²
2m-{n+[4m-3(m+2n)]}-5n,=2m-﹛n+[4m-3m-6n]﹜-5n=2m-﹛n+m-6n﹜-5n=2m-m+5n-5n=m=2/3
再求值m平方+m-2分之1+m除于m-2+m+2分之3
m的平方/(m-2)+4/(2-m)=m^2/(m-2)-4/(m-2)=(m^2-4)/(m-2)=(m+2)(m-2)/(m-2)=m+2当m=1/√(3-2)=1/1=1,故原式=1+2=3.再
m^2(m+3)+2m(m^2-1)-(m^4+m^3-m^2)/1/3m=m^3+3m^2+2m^3-2m-3(m^3+m^2-m)=3m^3+3m^2-2m-3m^3-3m^2+3m=mm=201
=m/(m+3)-6/(m²-9)*(m-3)/2=m/(m+3)-3/(m+3)=(m-3)/(m+3)=-5/1=-55x-4/x-2=4x+10/(3x-6)-1两边同乘(x-2)(3