先化简x²-1分之x²-2x÷(x-1-x+1分之2x-1)

x^2-1=(x+1)(X-1)x^2-2x+1=(x-1)^2第一项为（X+1）/(x-1)第二项为-x(x+1)so最后-1/x(x-1)

x满足方程x-1分之x+x分之1=1得x²+x-1=x²-x得x=1/2（x+1分之3-x+1）÷x+1分之x²-2x=[（x+1)分之(4-x²）]×[(x&

x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/

先化简,再求值:(x平方-1)分之(3x-3)÷(x+1)分之(3x)-(x+1)分之1,其中x=2=3(x-1)/(x+1)(x-1)×(x+1)/(3x)-1/(x+1)=1/x-1/(x+1)=

（3-x分之x-1）平方÷（x平方-6x+9分之9-x平方）平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]

{[(x+2)/(x^2-2x)]-[(x-1)/(x-2)]}/[(x+3)/x]={[(x+2)/(x^2-2x)]-[(x^2-x)/(x^2-2x)]}*[x/(x+3)]=[(-x^2+2x

你写的看不懂分子分母的代数式用括号括起来否则分不出来先通分【（（x-2）(x+2)-x(x-1)）/x(x+2)(x+2)】(x+2)/(x-4)=(x-4)/x(x+2)(x-4)=1/x(x+2)

[(x-2)/（x^2+2x）-(x-1)/(x^2+4x+4)]÷(x-4)/(x+2)=[(x-2)/x（x+2）-(x-1)/(x+2)^2]*(x+2)/(x-4)=(x-2)/x(x-4)-

(x^2-2x分之x+2-x^2-4x+4分之x-1)/x分之4-x=[(x+2)/(x(x-2)-(x-1)(x-2)^2]/(4-x)/x=[(x+2)(x-2)-x(x-1)/x(x-2)^2]

x分之4再问：有过程吗他那个是x-1分之1-x+1分之1的再答：[1/(x-1)-1/(x+1)]/[x/（2x方-2）]=[2/（x方-1）]*[2（x方-1）/x]=（2*2）/x=x/4

[（x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2=(2x-1)/x(x+1

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=

原式=[(x-1)/(x+1)+2x/(x²-1)]÷1/(x²-1)=[(x-1)/(x+1)+2x/(x²-1)]×(x²-1)=(x²-1)×(

x^2-x-1=0x^2=x+1(x分之x-1—x+1分之x-2)÷x的平分+2x+1分之2x的平分-x=((x-1)(x+1)-x(x-2))/x(x+1)÷(x(2x-1)/(x+1)^2)=((

（x²-1分之x-3）÷（x²+2x+1分之x²-2x-3)-(x+1分之1）=(x-3)/(x+1)(x-1)×(x+1)²/(x-3)(x+1)-1/(x+

(x²-1分之x²+1)-(x-1分之x-2)÷(x分之x-2)=(x+1)(x-1)分之(x²+1)-(x-1)分之(x-2)*(x-2)分之x=(x+1)(x-1)分

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

原式=[2x(x+1)/(x+1)(x-1)-x(x-1)/(x-1)²]÷x/(x+1)=[2x/(x-1)-x/(x-1)]×(x+1)/x=x/(x-1)×(x+1)/x=(x+1)/