使用循环累加100以内的偶数之和
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/18 09:00:19
intsum=0;for(inti=1,i
#includeusingnamespacestd;voidmain(){inti,sum=0;for(i=2;i再问:i=2的话开始sum不应该等于1么?再答:最后输出的时候加了1,当然你在前面
store0tosume,sumofori=1to100ifi%2=0sume=sume+i&&偶数累加elsesumo=sumo+i&&奇数累加endifnext"1~100偶数累加和=",sume
publicclassTest{publicstaticvoidmain(String[]args){ints1=0;ints2=0;for(inti=1;i
dimheaslong,naslonghe=0n=1dohe=he+nn=n+1loopuntilln>100msgbox"累加和是:"&he‘以上是VB的写法.
intn=0;intsum=0;while(n
Console.WriteLine("请输入起点整数");intnumberOne=Convert.ToInt32(Console.ReadLine());Console.WriteLine("请输入
#includevoidmain(){inti,sum=0;for(i=1;i
intsum=0;for(inti=0;i
unsignedchari;unsignedintsum;sum=0;for(i=2;i
an=(2n)^2=4n^2S50=4x50x51x101/6=171700
什么语言?如果是VB:DimsasIntegerDimiasIntegers=0Fori=0to100Step2'i从0数到100,每隔两个数字数一次,所以就是0,2,4,6,8,...,100s=s
偶数:2468101214161820.(n+2)奇数:1357911131517.(x+2)n表示2x表示1
method1sum=0;for(i=1;i再问:可以解释下你用了那三种循环语句结构再答:for循环dowhile循环while循环
summary = 0for i in xrange(10): n = int(ra
2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70
sum=0;form=1:1000sum=sum+m;endsum
参考代码:n=111;Y=cos(1:n);A=zeros(n,1);for k=1:n,A(k)=2/n*sum(Y.*sin(2*pi*(1:n)*k/n));endsubplot&nb
(2+100)*25=2550
#includemain(){inti,s=0;for(i=0;i