2016威海,若x^-3y-5=0
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再问:谢谢,再答:不言谢!
1.特殊值法:令X=5,Y=3,代入(X+3Y):(Y-X)=7:-1.2.CosA=(AC^2+AB^2-BC^2)/(2*AC*AB)=1/5√2=>SinA=7/5√2S△ABC=1/2AB*A
函数y=2-ax+1的图象可看作把y=ax的图象先沿轴反折,再左移1各单位,最后向上平移2各单位得到,而y=ax的图象恒过(0,1),所以函数y=2-ax+1恒过(-1,1)点,所以命题p假,则¬p真
(y-x)(x-y)^3(y-x)^5=(y-x)[-(y-x)^3](y-x)^5=-(y-x)^(1+3+5)=-(y-x)^9=(x-y)^9
x/y+y/x=(x²+y²)/xy=[(x+y)²-2xy]/xy=(x+y)²/xy-2=25/3-2=19/3
∵f(x-4)=f(x)-f(3),∴取x=2,得f(-2)=f(2)-f(3),即f(3)=f(2)-f(-2)∵y=f(x)是奇函数,∴f(-2)=-f(2)因此,f(3)=f(2)-f(-2)=
x=三分之五y代入x+y分之x-y消去y得:四分之一
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
3x+4y=x+2y+62x-x+4y-2y=62x+2y=6x+y=6/2x+y=3
(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10
x+y=0x=-yx/y=y/x=-13x-10+3y+y/5x=3(x+y)-10+y/5x=0-10-1/5=-10.2
3x-5y=0,则x+y/x=(8/5),x-y/y=(2/3),2x-3y/2x+3y=(1/19)因为3x-5y=0所以3x=5y设x=5,y=3,可以解得3x-5y=0,则x+y/x=(8/5)
再答:2016次方,和绝对值里面不可能为负,所以只能所有的都等于0
若x-y/x+y=5则x-y=5(x+y)所以求x-y/2x+2y+5x+5y/3x-3y=5(x+y)/[2(x+y)]+5(x+y)/3(x-y)=5/2+5(x+y)/[3*5(x+y)]=5/
(1)设抛物线的函数表达式为y=a(x-1)(x+3)∵抛物线交y轴于点E(0,-3),将该点坐标代入上式,得a=1∴所求函数表达式为y=(x-1)(x+3),即y=x2+2x-3;(2)∵点C是点A
(3x+2y)/(2x-5y)分子分母同时除以y=(3x/y+2y/y)/(2x/y-5y/y)=(3x/y+2)/(2x/y-5)=(3*4/3+2)/(2*4/3-5)=6/(-7/3)=-6*3
x(x*x-1)+x(5-x*x)-6y+7=-x+5x-6y+7=2(2x-3y)+7=2*(-4)+7=-8+7=-1再问:能在写详一点吗-x+5x-6y+7再答:x(x*x-1)+x(5-x*x
连MP,过M作MA⊥PQ于A,则PB=MA=2,设⊙M的半径为R,则MP2=MA2+PA2,即R2=22+(R-1)2,解得R=52,故选B.
(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧
2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6