代数式x-1分之x 2除以x-1分之x有意义,则x的取值范围是
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原式=(x^2-1)/x÷(x^2+x)/x^2=(x-1)(x+1)/x*x^2/x(x+1)=x-1当x=2时,原式=2-1=1
x≠-2,-3,-4
分母和除数不等于0‘x+2≠0x+4≠0且(x+3)/(x+4)≠0所以x≠-2且x≠-3且x≠-4
取值范围:x不等于-2、-3、-4;当X=-1时,代数式值为0
原式=x+2分之x∵分式的分母不能为0∴x+2≠0,x≠﹣2则x的取值范围是x≠﹣2
再答:望采纳,谢谢
(1-x+2分之3)除以x+2分之1-x的平方=(x+2-3)/(x+2)÷(x-1)²/(x+2)=(x-1)/(x-1)²=1/(x-1)
再问:呵呵你写错了再问:是2分之x
原式=(x+1)/(x-1)-x(x-2)/(x+1)(x-1)÷(x-2)(x+1)/(x+1)²=(x+1)/(x-1)-x/(x-1)=(x+1-x)/(x-1)=1/(x-1)请好评
原式=[(x²-4x+4)/(x²-4)]÷[(x²-2x)/(x+2)]-(1/x)+1={(x-2)²/[(x+2)(x-2)]}÷[x(x-2)/(x+2
[(x+3)/(x-3)]/[(x+2)/(x-4)]=[(x+3)(x+2)]/[(x-3)(x-4)](x-3)(x-4)≠0即x≠3且x≠4
这道题,谁要是能理解是什么式子,就已经是大神了
首先两个分母不等于0x-1≠0x≠1x+2≠0,x≠-2除数不等于0(x-1)/(x+2)≠0x-1≠0x≠1所以x≠-2且x≠1
x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
原式=(x-1)(x+1)/(x+2)*(x+2)/x-1=x+1然后代入数值即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
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