从键盘输入一个数,将其按倒序输出

Function Exchange(ByVal num As Integer)    If num 

#include"stdio.h"voidmain(){charc;c=getchar();if(c>='A'&&c

DimxAsInteger,sAsString,dAsStringRandomizex=Int(Rnd()*9000+1000)s=Str(x)d=Right(s,1)+Mid(s,4,1)+Mid(

#include#include#defineN5intmain(){inti,j,a[10],sum=0,temp;floataverage;for(i=0;i

#include <stdio.h>#include <string.h>int main(){    c

#include#includevoidmain(void){inti,j=0;chars[20],a[10]={0},b[10]={0};gets(s);for(i=0;i=0;i--)b[j++]

我忘了,http://wenku.baidu.com/view/d353704b852458fb770b5688.html百度的,冒泡法,能解决

#include"stdio.h"#include"math.h"intmain(void){charinput[100];printf("Pleaseinputthearray(int):");ge

给你举个例子吧!#include#defineN5main(){intnum[N+1]={1002,1003,1006,1008,1010};/*必须多开辟一个存储单元*/inti=0,j=0,new

#include"stdio.h"voidmain(){\x09inta;\x09intb[3];\x09intcount=0;\x09printf("请输入一个数");\x09scanf("%d",

intmain(){intn,n1,n2;cin>>n1;n2=n1%100;n1=n1/100;n=n1;n2=n2%10;n1=n1/10;n=n+10*n1+100*n2;returnn;}

#includevoidmain(){usignedintinput,output=0;coutinput;for(inti=intput;i>0;i/=10){intx=i%10;if(i%2==0

#include#includeintmain(){scanf("%lf",&k);printf("%d\n",(int)sqrt(k));}

从键盘输入一个自然数N(

#include"stdio.h"intmain(){inti,j;inta[12];for(i=1;i

#includeusingnamespacestd;intmain(){char*str=newchar[255];cin>>str;cout再问：看不等，我刚学编程再答：把输入的数字放到一个指针数组

PrivateSubForm_Load()DimxAsInteger,yAsInteger,zAsIntegerDimdiyigeAsIntegerDimdiergeAsString,disangeA

你这个程序不是在开玩笑吧,错的快没对的了,经过我全面整容以后程序如下：#include//包含输入输出函数voidmain(){chara,b,c;intn=0;//变量的定义必须放到最前面print

ntmain(intargc,char*argv[]){charsound[10][5]={"yi","er","san","si","wu","liu","qi","ba","jiu","shi"}

importjava.applet.*;importjava.awt.*;importjava.awt.event.*;publicclassTest3_2extendsAppletimplement