(m²-3n²) (m-3n)-(4m²-9n²) (2m-3n)

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(m²-3n²) (m-3n)-(4m²-9n²) (2m-3n)
(m-n-3) 平方

(m-n-3)^2={(m-n)-3}^2=(m-n)^2-6(m-n)+9=m^2-2mn+n^2-6m+6n+9

计算(m+n)^3-(n+m)(m-n)^2

(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2

计算n^3/m^3-m^3/n^3-(n/m-m/n)

n^3/m^3-m^3/n^3-(n/m-m/n)=(n/m-m/n)(n^2/m^2+1+m^2/n^2)-(n/m-m/n)=(n/m-m/n)(n^2/m^2+1+m^2/n^2-1)=(n/m

(2m+3n)(2m-3n)-(3m-2n)(3m+2n)

(2m+3n)(2m-3n)-(3m-2n)(3m+2n)=(4m²-9n²)-(9m²-4n²)=4m²-9n²-9m²+4n&

已知m/n=5/3,求m/(m+n)+m/(m-n)-n平方/(m平方-n平方)

m/(m+n)+m/(m-n)-n²/((m²-n²)=(m²-mn+m²+mn-n²)/(m²-n²)=(2m&sup

(m+n)(m-n)/m+3n 怎么化简

这已经是最简形式了.

(n-m)^3×(m-n)^2-(m-n)^5

(n-m)^3×(m-n)^2-(m-n)^5=-(m-n)^3*(m-n)^2-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

(3m-2n)^+(3m+2n) (3m-2n)-9(m+n)^

(3m-2n)²+(3m+2n)(3m-2n)-9(m+n)²=(3m-2n)²-9(m+n)²+(3m+2n)(3m-2n)=(3m-2n+3m+3n)(3m

3(m+n)+1.5(m-n)

3(m+n)+1.5(m-n)=3m+3n+1.5m-1.5n=4.5m+1.5n

[(m-n)^2*(m-n)^3]^2/(m-n)^4

设m-n为a(a^2*a^3)^2/a^4=a^6即(m-n)^6

因式分解(n-m)^3(m-n)^2-(m-n)^5

解原式=-(m-n)³(m-n)²-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5

(2m+3n)(3m-2n)-(3m-2n)(3m+2n)

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化简-3n+5m-[m-5(m-n)+m]

-3n+5m-[m-5(m-n)+m]=-3n+5m-[m-5m+5n+m]=-3n+5m-[-3m+5n]=-3n+5m+3m-5n=8m-8n

已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?

m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=[m(m-n)+n(m+n)-n^2]/(m^2-n^2)=m^2/(m^2-n^2)=1/(1-(n/m)^2)=1/(1-(3/2)^2

已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))

已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)

[5m(3m-n)+2n(n-3m)]/(3m-n)

[5m(3m-n)+2n(n-3m)]/(3m-n)=[5m(3m-n)-2n(3m-n)]/(3m-n)=(5m-2n)(3m-n)/(3m-n)=5m-2n

[2(m+n)^5-3(m+n)^4+(-m-n)^3]÷[2(m+n)^3]

原式=2(m+n)^5÷[2(m+n)^3]-3(m+n)^4÷[2(m+n)^3]+(-m-n)^3÷[2(m+n)^3]=(m+n)^2-3(m+n)/2-1/2再问:��Ҳ�㵽��һ���ˣ��

3m(m-n)-2n(m-n)的平方

3m(m-n)-2n(m-n)²=(m-n)(3m-2mn+2n²)