(a 2)(a 4) 1分解因式
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解题思路:分解因式解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph
1-6y+y²=y²-6y+9-8=﹙y-3﹚²-8=﹙y-3-2√2﹚﹙y-3+2√2﹚.
=a^8(a²+a-1)+a^5(a²+a-1)+a^2(a²+a-1)=(a^8+a^5+a^2)(a²+a-1)=0
xg+(2人+1)x2+(人2+2人-1)x+(人2-1)=xg+(2人+1)x2+(人2+2人)x-x+(人2-1)=(xg-x)+[(2人+1)x2+(人2+2人)x+(人2-1)]=x(x2-1
7(m+n)2=14(m+n)吗?你确定你打的格式对了?
原式=(a-1)2-b2=(a-1+b)(a-1-b).故选C.
(m+n)²-n²=(m+n-n)(m+n+n)=m(m+2n)(3x-y)²-(x+3y)²=(3x-y-x-3y)(3x-y+x+3y)=(2x-4y)(4
=x^2+4x+3+1=x^2+4x+4=(x+2)^2
(1)24m2+18m=6m(4m+3);(2)9a2-14b2=(3a+12b)(3a-12b);(3)m(x-y)+2(y-x)=m(x-y)-2(x-y)=(x-y)(m-2);(4)(x+y)
第一题选D.分解完是(b-a)(b+a)m^2-4m^2...这个确定是这样嘛?是这样的话就是-3m^2.我猜是4次方吧...m^4-4m^2=m^2(m+2)(m-2)m^2-4m^4=m^2(1+
3a2+6a+3,=3(a2+2a+1),=3(a+1)2.故答案为:3(a+1)2.
(1)原式=5x(x-3)+2y(x-3)=(x-3)(5x+2y),(2)原式=3b[a3-(3b)3]=3b(a-3b)(a2+9b2-3ab).(3)原式=-(a4-24)=-(a2+4)(a-
(b2+a2-c2)2-4a2b2,=(b2+a2-c2+2ab)(b2+a2-c2-2ab),=[(b+a)2-c2][(b-a)2-c2],=(b+a+c)(b+a-c)(b-a+c)(b-a-c
解题思路:提取公因式解答解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq
a3+a2-a-1=(a3+a2)-(a+1)=a2(a+1)-(a+1)=(a+1)(a2-1)=(a+1)(a+1)(a-1)=(a-1)(a+1)2.故答案为:(a-1)(a+1)2.
解题思路:利用立方差公式灵活进行分析。解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/includ
a^4(b^2-c^2)+b4(c^2-a^2)+c4(a^2-b^2)=-c^2a^4+c^2b^4+(a^4b^2-a^2b^4)+c4(a^2-b^2)=-c^2(a^4-b^4)+a^2b^2
18a2-50=2(9a2-25)=2(3a+5)(3a-5).故答案为:2(3a+5)(3a-5).
x2-a2-2a-2x=(x^2-2x+1)-(a^2+2a+1)=(x-1)^2-(a+1)^2=(x-1+a+1)(x-1-a-1)=(x+a)(x-a-2)
8(a2+1)-16a=8(a2+1-2a)=8(a-1)2.故答案为:8(a-1)2.